u^2-2u+2=(u^2-2u-u+2)

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Solution for u^2-2u+2=(u^2-2u-u+2) equation: 



u^2-2u+2=(u^2-2u-u+2)

We move all terms to the left:

u^2-2u+2-((u^2-2u-u+2))=0



We calculate terms in parentheses: -((u^2-2u-u+2)), so:

(u^2-2u-u+2)

We get rid of parentheses

u^2-2u-u+2

We add all the numbers together, and all the variables

u^2-3u+2

Back to the equation:

-(u^2-3u+2)



We get rid of parentheses

u^2-u^2-2u+3u-2+2=0

We add all the numbers together, and all the variables

u=0

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